Question

An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30ｺ. The heights of the tower is:

Answer 1

let the height above the persons height be h so total height of the tower =

h + 1.6 m 
from the question we can see tan 30 = h/203 ⇒ h = 203√3 = 351.596 m 

so total height of the tower is 351.596  + 1.6 m = 353.196 m  ANSWER

Answer 2

Answer:

21.6

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