find the 10th term form the end of an ap 8,10,12...126?
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formula is { l-(n-1) d } l is last term i.e. 126
=126-9*2 =108
=126-9*2 =108
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Solution:
Here common difference = 10 - 8 = 2
First Term = 8
In A.P ,
Nth term = first term + (term Number - 1 )*Common Difference
here nth term = 10 ,
first term = 8
term number = 10
common difference = 2 ,
hence ,
10th term = 8 + (10 -1 )2
=8+9*2
= 8 + 18
= 26
hence 10th term in the mentioned series is 26 .
Thank You!!
Here common difference = 10 - 8 = 2
First Term = 8
In A.P ,
Nth term = first term + (term Number - 1 )*Common Difference
here nth term = 10 ,
first term = 8
term number = 10
common difference = 2 ,
hence ,
10th term = 8 + (10 -1 )2
=8+9*2
= 8 + 18
= 26
hence 10th term in the mentioned series is 26 .
Thank You!!
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