Question

An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:

Answer 1

The observer is 203m away from the tower; and can see the top at an angle of 30°.

Let h be the height of the tower. Then:

h/203=tan 30°

h=203 tan 30

=203√3 / 3

=117.2021

Plus, we add the height of the observer:

h’=117.2021 + 1.6

=118.8m