Question

An observer 1.7m tall is 20 root 3 away from a tower the angle of elevation from the eye of an observer to the top of tower 30 find height of tower

Answer 1

Solution :-

Let AB be the height of the tower and DE be the height of the observer.

Then,

In Δ ACD,

AC/DC = tan 30°

⇒ x/√30 = tan 30° = 1/√3

⇒ x = 20 m

⇒ AB = 20 m + 1.7 m 

= 21.7 m

So, the height of the tower is 21.7 m

Answer.