An Observer 2 Meter Tall Is 30√3 Meter Away From A Tower.The Angle Of Elevation From His Eye To The Top Of The Tower is 30° . Determine The Hight Of Tower.
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divyansh8765:
your answre is right and your explanation is also good
Thank u
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Tan 30°=Ab/30√3
1/3 = Ab/30√3
30√3/3 =ab
30 cm = ab
Hope this is useful
1/3 = Ab/30√3
30√3/3 =ab
30 cm = ab
Hope this is useful
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