Question

An observer in a train moving with a uniform velocity finds that a car moving parallel to the train has a speed of
10 km/h in the direction of motion of the train. An object falls from the car and the observer in the train notices
that the car has moved on for one minute, turned back, and moved with a speed of 10 km/h and picked up the
object two minutes after turning. Find
(a) The velocity of the train relative to the ground and
(b) The velocity of the car during its forward and reverse journeys
Assume that the object comes to rest immediately after fall from the point of view of the observer on the ground​

Answer 1

Answer:

10/3 km/Hr

40/3 & 20/3 km/Hr

Step-by-step explanation:

Let say velocity of the train relative to the ground = V km/Hr

An observer in a train moving with a uniform velocity finds that a car moving parallel to the train has a speed of 10 km/h in the direction of motion of the train

=> Car Speed = V + 10 km/Hr

Distance covered in 1 min  = (V + 10) * 1/60

observe  that moved with a speed of 10 km/h

=> Actual Speed = 10 - V km/hr

Distance Covered in 2 min = (10 - V)* 2/60

(V + 10) * 1/60  = (10 - V)* 2/60

=> V + 10 = 20 - 2V

=> 3V = 10

=> V = 10/3 km/Hr

The velocity of the train relative to the ground  = 10/3 km/hr

Velocoty of Car During Forward motion = 10 + 10/3 = 40/3 km/hr

Velocity of Car During reverse motion = 10 - 10/3 = 20/3 km/hr

(V + 10) * 1/60 = 10 * 2/60

=>