An octagon ha three equal angle each of measure 115°.If all the remaining angles have equal measure,find the measure of each of these remaining angles
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Answer:
Let x be the angle of each of the remaining angles.
Any polygons have a sum of interior angles equal to (n-2)*180 where n is the number of sides of the polygon.
∴ Sum of interior angles of an octagon=(8-2)*180=1080
∴(3*115)+5x=1080
345+5x=1080
5x=735
x=147
Hence the magnitude of each of the remaining angles.
Hope it helps :)
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