An octagonal die with letters A,B,C,D,D,E,C,A written on its faces is rolled once. Find the probability that the letter that turns up is (a)A (b) D
Pls do it with proper steps
insiyahr:
Hey Ritika
Do you know the perfect answer for this question????
It is a sum of probability
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(a)p(getting A)=2/8=1/4
(b)p)getting D)=2/8=1/4
(b)p)getting D)=2/8=1/4
I need steps pls can you add then
Them*
Answered by
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Answer:
1/4, 1/4
Step-by-step explanation:
Total number of faces on the die = 8.
(a)
Number of faces having A on it = 2.
P(getting A) = (Number of faces having A)/(Total number of faces on die)
= 2/8
= 1/4.
(b)
Number of faces having having D on it = 2.
P(getting D) = (Number of faces having D)/(Total number of faces on die)
= 2/8
= 1/4.
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