Question

An octahedral complex absorbs in 545nm. Then it's respective tetrahedral field spiliting(Delta tet) would be?​

Answer 1

Explanation:

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Answer 2

The respective tetrahedral splitting energy would be $\Delta_t =1.621\times 10^{-19} J$

Explanation:

The wavelength of the absorbed radiation by the given octahedral complex is 545 nm$, \lambda = 545\times 10^{-9} m$

Hence, the Energy of this radiation$, E = \frac{hc}{\lambda}$, where h is Planck's constant and c is the speed of light

$E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{545\times 10^{-9}}$

$E = \frac{19.878\times 10^{-26}}{545\times 10^{-9}}$

$E = {0.0364\times 10^{-17}}$

$E = {3.64\times 10^{-19}} J=\Delta_0$ (Octahedral field splitting energy)

The octahedral crystal field splitting $\Delta_o$ is related to tetrahedral crystal field $\Delta_t$ as

$\Delta_t =\frac{4}{9}\Delta_0$

$\Delta_t =\frac{4}{9}(3.64\times 10^{-19})$

$\Delta_t =1.621\times 10^{-19} J$