An oil drop has 6.39 x 10^-19C charge. Find out the number of electrons in this drop.
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Answered by
12
Answer:
charge present in oil drop ,
=6.39x 10^-19
charge of an electron is
= 1.6 x 10^-19
no. of electron ,
=(6.39x10^-19)/(1.6 x 10^-19)
4 electrons
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