An oil funnel of tin sheet consists of a cylindrical portion 10 cm long attached to a
frustum of a cone. If the total height be 22 cm, diameter of the cylindrical portion be
8 cm and the diameter of the top of the funnel be 18 cm as shown in the given
figure, find the area of the tin required to make the funnel.
Answers
Answered by
3
Answer:
Step-by-step explanation: Given, the total height is 22. Length (or height) of cylinder is 10.
Hence, height of frustrum is 12
Area of frusturm (CSA) = πl(R1+R2)
Put R2 = 18/2 =9
Put R1 = 8/2 = 4
L = √(h²+(R2-R1)²)
L = √(12²+(9-4)²)
L = √144+25
L = √169 = 13
Area of frusturm = 3.14× 13 × (4+9)
= 530.66
Now, area of cylinder (CSA) = πRL = πR1H = 3.14×4×10
= 125.60
Total area = 530.66+125.60 = 656.26 cm²
Similar questions