an open box at the top has its outer dimension 10 cm 9 cm and 2.5 cm and its thickness is 0.5 cm find the volume of the metal used
Answers
Answered by
3
volume = lbh - lbh
= 11×10×3.5 - 10 ×9+×2.5
=160
= 11×10×3.5 - 10 ×9+×2.5
=160
Answered by
3
Step-by-step explanation:
Given:
- Length = 10 cm.
- Breadth = 9 cm.
- Width = 2.5 cm.
To find:
Find the volume of metal ?
Solution:
We know that Volume of the outer metal= l * b * h
=> 10 * 9 * 2.5
=> 225 cm^3.
Given that thickness is 0.5 cm.
=> Length = 10 - (0.5 + 0.5)
= 9 cm.
=> Breadth = 9 - (0.5 + 0.5)
= 8 cm.
=> Width = 2.5 - (0.5)
= 2 cm.
So, volume of the inner metal = l * b * h
=> 9 * 8 * 2
=> 144 cm^3.
Now,
Volume of the metal = 225 - 144 => 81cm^3.
Therefore, Volume of the metal = 81 cm^3.
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