an open box is to be made from a rectangular cardboard of side 35cm and 20cm by cutting equal square from each corner and then bending up the edges. If the base area of box thus formed is 250cm square find the length of the side of the square cut from each corner
Answers
Answered by
2
The figure for the box
Figure

The volume of the box is
V=(30−2x)(16−2x)xV=(30−2x)(16−2x)x
Simplifying the expression, we have
V=480x−92x2+4x3V=480x−92x2+4x3
Differentiating the equation with respect to xx
V′=480−184x+12x2V′=480−184x+12x2
Setting V′=0V′=0
0=480−184x+12x20=480−184x+12x2
Reducing the equation to lowest terms
0=120−46x+3x20=120−46x+3x2
Using the quadratic formula
x=−(46)±√(−46)2−4(3)(120)2(3)x=−(46)±(−46)2−4(3)(120)2(3)
x=46±262(3)x=46±262(3)
x=103,12x=103,12
Since xx cannot be 1212 because the width becomes negative, thus x=103
Figure

The volume of the box is
V=(30−2x)(16−2x)xV=(30−2x)(16−2x)x
Simplifying the expression, we have
V=480x−92x2+4x3V=480x−92x2+4x3
Differentiating the equation with respect to xx
V′=480−184x+12x2V′=480−184x+12x2
Setting V′=0V′=0
0=480−184x+12x20=480−184x+12x2
Reducing the equation to lowest terms
0=120−46x+3x20=120−46x+3x2
Using the quadratic formula
x=−(46)±√(−46)2−4(3)(120)2(3)x=−(46)±(−46)2−4(3)(120)2(3)
x=46±262(3)x=46±262(3)
x=103,12x=103,12
Since xx cannot be 1212 because the width becomes negative, thus x=103
Similar questions