an open box whose shape is a cuboid has a dimensions 9cm by 7cm by 6cm. find (i) the outer surface area of the box. please i need step by step explanations
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GIVEN THAT LENGTH , BREADTH AND HEIGHT OF CUBOID IS 9CM,7CM,AND 6CM RESPECTIVELY....
i. TSA OF CUBOID = 2 (LB +BH+HL)
= 2(9*7)+7(6)+6(9)
= 2(63+42+54)
=2(159)
= 318 cm^2 ....
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