Question

AN open flask was heated from 27 degree Celsius to 227 degree Celsius . Calculate the volume of flask if 0.1 decimetre cube of air was expelled from the flask at 227 degree Celsius

Answer 1

V1/V2=T1/T2
V1/0.1=300/500
V1=.06 cubic decimeter or .06 litre

Answer 2

Answer : The volume of flask at $27^oC$ is, 0.06 L

Solution :

According to the Charles's law, the volume of gas is directly proporytional to the temperature if the gas a constant pressure and number of moles of gas.

$V\propto T$

or,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1$ = initial volume of gas

$V_2$ = final volume of gas = $0.1dm^3=0.1L$

$T_1$ = initial temperature of gas = $27^oC=273+27=300K$

$T_2$ = final temperature of gas = $227^oC=273+227=500K$

Now put all the given values in the above equation, we get the initial volume of gas.

$\frac{V_1}{300K}=\frac{0.1L}{500K}$

$V_1=0.06L$

Therefore, the volume of flask at $27^oC$ is, 0.06 L