Question

An open metal bucket is in the shape of a frustum of a cone, mounted on a hollow cylindrical base made of the same metallic sheet. Find the area of the metallic sheet used to make the bucket
3 points
CSA of frustum - CSA of cylinder + area of base
CSA of frustum + CSA of cylinder + area of base
CSA of frustum + CSA of cylinder - area of base​

Answer 1

Answer:

The Area of the metallic sheet is 4860.9 CM²

Step-by-step explanation:

Area of the metallic sheet = CSA of frustum + CSA of cylinder + area of circle

CSA of frustum :- π  (r 1 + r 2 ) l

h = 34 cm because height of cylinder is 6 cm.

l = √h²+(r1²-r2² )

l = √34²+ ( 45/2 ² - 25/2 ² )

=35.44 cm

r1 = 45/2 and r2= 25/2

CSA =  π ( 45/2 + 25/2 ) 35.44

= 1240.4  π  CM²

CSA of cylinder :- 2πrh

=2 π 25/2 x 6

= 150π CM²

A of circle :- πr²= π x (25/2)²

= 156.25π CM²

Area of the metallic sheet = 1240.4  π + 150π + 156.25π

= π ( 1240.4+ 150 +156.25 )

=4860.9 CM²

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