Physics, asked by alzebraloverAnud, 21 days ago

An open resonating tube has fundamental frequency of n. When half of its length is dipped into water, then its fundamental frequency will be:
1)n. 2)n/2. 3)2n. 4)3/2n
Plz answer the question stepwise​

Answers

Answered by BrainIyRaftaar
0

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