Question

An open tank made up of 4m wide sheet. It has a dimension of 15m×12m×2m. Find the cost of sheet at the rate of 22.50 per m...


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Answer 1

Answer:

1923.75

Step-by-step explanation:

Note: I am considering height as 3 m as per your request.

Length of the tank = 15 m.

Breadth of the tank = 12 m.

Height of the tank = 3 m.

(i)

Area of base = length * breadth

                     = 15 * 12

                     = 180 m².

Thus, Area of base = 180 m²

(ii)

Area of lateral surface = 2 * (l + b) * h

                                     = 2(15 + 12) * 3

                                     = 162 m².

Total area of the open tank = 180 + 162 = 342 m².

Thus, Area of the sheet required = 342 m².

(iii)

Given, Width of the tank = 4 m.

∴ Length of the tank = (Area)/Width

                                  = 342/4

                                  = 85.5 m.

Given, Cost of 1 m of sheet = 22.50.

Then, Cost of 85.5 m of sheet = 85.5 * 22.5

                                                  = 1923.75.

Therefore, Cost of sheet = 1923.75.

Hope it helps!

Answer 2

$\huge \pink{ \bf{Hey \: there !! }}$


$\huge \bf \underline {Given :- }$

→ Length of the tank = 15 m.

→ Breadth of the tank = 12 m.

→ Height of the tank = 2 m.

→ Width of the sheet = 4 m.


$\huge \red{\mid\bf \underline { \overline{Solution :- } } \mid}$



As we know tank is in the shape of cuboid .

And, it is open tank .

So, the Total surface area [ TSA ] of open tank = Lateral surface area + area of base .

= 2( l + b )h + l × b .

= 2( 15 + 12 ) × 2 + 15 × 12 .

= 4 × 27 + 180 .

= 108 + 180 .

= 288 m² .


Thus, Total area of sheet required = 288 m² .

And, it is given : Width of sheet = 4 m.

→ Area = Length × Width .

$\sf \implies Length = \frac{area}{width} \\ \\ \sf \implies Length = \frac{288}{4}. \\ \\ \sf \large\therefore Length = 72m.$


Therefore, cost of sheet of length 72m at the rate of 22.50 per m²
$\sf = 72 \times 22.50. \\ \\ \sf \huge \blue{ \boxed{ \boxed{ \underline{= Rs \: 1620.}}}}$



✔✔ Hence, it is solved ✅✅.



$\huge \orange{ \boxed{ \boxed{ \mathcal{THANKS}}}}$