An open U-tube of uniform cross -section contains mercury. When 40.8 cmof water is poured into one limb of the tube, then the difference in levels of liquids of the two sides is (Density of water 3
1 / gm cm and mercury 3 Hg gm cm 13.6 / ) 1. 23.2cm 2. 37.8cm 3. 21.2cm 4. None
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Δh = 25.2 cm
Explanation:
An open U-tube of uniform cross -section contains mercury. When 40.8 cm of water is poured into one limb of the tube, then the difference in levels of liquids of the two sides is 25.2cm
Density of water = 1
Density of mercury = 13.6
PA = PC
Pw. g. h1 = 2y. pm.g
1 * 9.8 * 27.2 = 2y * 13.6 * 9.8
27.2y = 27.2
Therefore y = 27.2/27.2 = 1cm
Δh = h1 - h2 = 27.2 - 2y = 25.2 cm
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