Chemistry, asked by stephymolsunny1121, 1 year ago

An open vessel at 27 degree heated until one fifth part of the air in it has been expelled.Assuming that volume of the vessel remains constant,the temperature to which vessel has been heated

Answers

Answered by DSamrat
2
volume of vessel = volume of air in it
(as air is a fluid ) and let it be V initially.
initial mass be m
initial temperature=27 degree C=300K
pressure on the air will be atmospheric say P.

volume of air after heating= V as it remains constant
mass remaining will be 4/5m as m is directly proportional to volume.
pressure will be same as atmospheric, P

let temperature be x


Now as PV=mRT

so, p1v1/m1T1=p2v2/m2T2=R
so, PV/m×300=PV / 4m/5 × X
so, X=300×5/4 = 375 K

So, temperature to which it has been heated is 375K i.e., 102 degree C.

Thanks. Mark it as brainliest .

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