An open vessel at 27°C is heated until three fifth of the air in it has been expelled .Assuming volume of the vessel constant, find yhe temperature to which the vessel has been heated.
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Since the vessel is open to the air the number of molecules of air is not fixed, but the pressure and temperature are. As the vessel is heated air will escape from it so that the pressure remains constant.
n1T1 = n2T2 ................... from PV=nRT
T2 = n1T1 / n1 ................ solve for T2
T2 = 5/5 x 300K / 2/5
T2 = 750K ............ or ............. 477C
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