Question

Question :
Boron is unable to form BF6^-3 ion. Explain.

Answer 1

$\huge{\boxed{\boxed{\mathfrak{\red{Answer}}}}}$

Due to non availability of d orbital

$\huge{\underline{\mathscr{\orange{Reason}}}}$

Due to non availability of d orbitals boron is unable to expand it's octet. Therefore the maximum covalence of boron cannot exceed 4.

Answer 2

$\huge\red{\boxed{\bold{Answer}}}$

• Boron is a non-metallic element.

• It is electron-deficient.

• It does not possess d orbitals in its valence shell.

• Therefore, boron is unstable to form BF6 3- ion.

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