Question

An open vessel is kept at 300 k. If this vessel is heated to 427 degree Celsius then fraction of amount of air escape from the vessel will be
A. 1/7
B.2/7
C.3/7
D.4/7

Answer 1

Answer:

Option(D)

Explanation:

As the vessel is open, the pressure remains constant.

There is no change in the volume of the vessel. Hence, the volume also constant.

ACC to ideal gas equation, PV = nRT

T₁ = 300 K, T₂ = 700 {∵ 427 + 273.15 = 700 K}

Now,

n₁/n₂ = T₂/T₁

=> 1/x = 700/300

Fraction of air present in vessel after heating = 3/7

Now,

Fraction of air getting out of the vessel = 1 - 3/7 = 4/7

Hope it helps!