An operator applies a force pf 200.0 N to the first piston of a hydraulic lift, which has an area of 5.4 cm^2 . what is the pressure applied to the hydraulic fluid ?
A. 3.7x10^1 Pa
B. 2.0x10^3 Pa
C. 3.7x10^3 Pa
D. 3.7x10^5 Pa
Answers
Answered by
0
Pressure = F/A. You have F. You have A. However Pascals (Pa) are N/m^2 so you'll need to convert the area to m^2.
Answered by
2
Answer:
D. 3.7*10^5 Pa
Explanation
We know that Pressure=Force/Area
Force is given as 200 N
We've to convert 5.4 cm^2 to m^2
For that divide 5.4 by 10^4
It will be 5.4*10^-4
Now we can put this in put formula
p=200/10^-4*5.4 = 200*10^4/ 5.4
200/5.4 is 37(approx)
37*10^4 or 3.7 * 10^5
hope it helped u
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