Question

An orange of radius 3.5cm contains 15 percent of its volume . Find how many oranges are required for gathering of 50 people, if each guest to be served with 250 ml juice.

Answer 1

Radius of one orange = 3.5 cm

$v = 4 \div 3\pi {r}^{3}$
Thus,

V = 4/3 x 22/7 x 3.5 x 3.5 x 3.5

V = 539/3 cm^3

But it contains 15% juice

Thus,

Juice in one orange = 15/100 x 539/3 = 26.95ml

No of people = 50

Amount that should be served to one = 250 ml

Thus,

Total juice required = 50 x 250 = 12500 ml

Thus,

No. Of oranges = 12500/26.95 = 463.8 which is approximately = 464 oranges.

Hope it helps :)

Answer 2

Answer:

Answer in the attachment

Step-by-step explanation:

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