Question

An ordinary six-faced die is thrown four times. What are the probabilities of obtaining 4,3,2,1&0 faces?​

Answer 1

Step-by-step explanation:

1/6

total faces of die is 6

probity of obtaining 4 3 2 1 s 0

is 1/6

Answer 2

Given:

An ordinary six-faced die is thrown four times. What are the probabilities of obtaining 4,3,2,1&0 faces?​

Solution:

Know that an ordinary six-faced dice is numbered from 1 to 6,

So that the probability of getting 0 is 0.

And the probability of getting  4,3,2, and 1 in a single roll is,

$\[ = \frac{4}{6}\]$

$\[ = \frac{2}{3}\]$

Since the dice is rolled four times,

Therefore the required probability is,

$\[ = {\left( {\frac{2}{3}} \right)^4}\]$

$\[ = \frac{{16}}{{81}}\]$

Hence, the required probability is $\[\frac{{16}}{{81}}\]$.