Question

an ore contains 15% of iron how much ore will required to get 36kg of iron

Answer 1

let the amount of ore be x
15/100×x=36
x=36×100/15
=12×20
=240 kg

Answer 2

Answer

Find out the  how much ore will required to get 36kg of iron .

To prove

Let us assume that the ore required for 36 kg of iron be x .

As given

an ore contains 15% of iron

36kg of iron

15 % is written in the decimal form .

$= \frac{15}{100}$

= 0.15

Than the equation becomes

x × 0.15 = 36

$x = \frac{36}{0.15}$

x = 240kg

Therefore 240kg ore will required to get 36kg of iron .