An ore contains 20 percent zinc. How many kg of ore will be required to get 45kg of zinc.
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given that an ore contains 20% zinc
let number of kg of ore required to get 45 kg zinc = x
20% of x = 45kg
⇒ 20/100 × x = 45kg
⇒ x/5 = 45kg
⇒ x = 5 × 45 = 225kg
hence 225 kg of ore will be required to get 45 kg zinc
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