An ore contains 20% zinc. How many kg of ore will be required to get 45 kg of zinc ?
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Answer:
225kg
Step-by-step explanation:
20% can also be written as 20/100
let us take the amount of ore required for 45kg zinc as x
∴According to the condition,
20/100=45/x
20/100 can be simplified to 1/5
∴1/5=45/x
crossmultiplying
1x=5×45
x=225
therefore 225kg of ore will be required
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