Question

An ore contains 20% zinc. How many kg of ore will be required to get 45kg of zinc

Answer 1

Let quantity of ore=x
20% of x = 45kg
20/100 of x =45kg - x/5 =45
x =45 *5 =225
Quantity of ore =225kg

Answer 2

$\textbf {\huge {ANSWER:}}$

Let the quantity of ore be = x

20% of x = 45

$= > \frac{20}{100} \times x = 45 \\ \\ = > x = \frac{45 \times 100}{20} \\ \\ = > x = 45 \times 5 \\ \\ = > 225$