An organic compound 'A' with molecular formula C2H6O on oxidation with alkaline KMnO4 given the compound 'B' to form a sweet smelling substance 'C'.
1)Name the compound 'A'&'B'.
2)Write the structural formula of 'C'.
3)Write the chemical equation involved.
Answers
Answered by
0
here a is dimethyl ether i.e ethanol..
b is ethanoic acid and c is ester..
CH3CH2OH+O=CH3CHO+H2O
b is ethanoic acid and c is ester..
CH3CH2OH+O=CH3CHO+H2O
Answered by
0
1. compound A is ethanol (C2H6O) which on oxidation with alkaline KMnO4 gives compound B that is ethanoic acid
2. compound C is Easter CH3COOCH2CH3
3. CH3COOH + CH3CH2OH ------------------------------> CH3COOCH2CH3. in presence of conc. H2SO4 ( Easter formation which has sweet smelling)
HOPE IT WILL HELP YOU
Similar questions