Question

an organic compound contain 52.14% carbon and 13.13% hydrogen of the molecular mass of the compound is 92 g mol^-1 find its empirical formula and molecular formula​

Answer 1

Answer:

Given that,C= 52.14%

H=13.13%

O= 34.73%

No. of moles of C= 52.14/12= 4.345

No.of moles of H= 13.13/1= 13.13

No.of moles of O= 34.73/16= 2.170

Therefore,the ratio of the atoms of C,H and O= 4.345 : 13.13 : 2.170 = 2 : 6 : 1

So,the empirical formula is C2H6O

Let the Molecular formula is (C2H6O)n

Then, molar mass = (2×12+1×6+16)n

= 46n

As the question, 46n = 46.07

or,n= 1

So,the molecular formula is (C2H6O)1= C2H6O i.e.the compound is ethanol or dimethyl ether

mark me brainliest