Question

An organic compound contains 12.8% carbon, 2.1% hydrogen and 85.1% bromine by mass. Calculate its empirical formula. (Atomic masses: Carbon=12, hydrogen=1, bromine=79.90) (Note: mention data, formula, calculation and result)

Answer 1

Moles of C =

12

12.8

=1.067

Moles of H $=$\dfrac{2.1}{1.008}=2.08$$

Moles of Br =

79.9

85.1

=1.065

C=

1.065

1.067

=1, H=

1.065

2.08

=2, Br=

1.065

1.065

=1

Empirical formula =CH

2

Br

Molecular formula =(CH

2

$Moles of C =1212.8=1.067$

Br)n

Empirical mass =93.9

Therefore n=

93.9

187.9

=2

Molecular formula =C

2

H

4

Br

2

Answer 2

Answer:

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