Question

an organic compound contains 39.5 % of carbon 6.4 % of hydrogen and 54.1 % of oxygen calculate the empirical formula of the compound​

Answer 1

Answer:

Explanation:

Percentage of oxygen = 100- (39.5 + 6.4) = 100- 45.9 = 54.1

∴ Empirical formula =CH2O

Molecular mass = Eq. mass x basicity =60×1=60

Empirical formula weight =CH2O=12+2+16=30

Nows 30 n = 60 ⇒n=2

∴ Molecular formula = (Empirical formula) x n =(CH2O5)2=C2H4O2