Question

An organic compound contains carbon and Hydrogen,hydrogen has 92% and carbon has 3% its emperical formula will be?

Answer 1

H = 92 ÷ 2 = 46   C = 3 ÷ 12 = 0.25  O = 15 ÷ 16 = 0.93   Divide by smallest quotient  H = 46 ÷ 0.25 = 184  C = 0.25 ÷ 0.25 = 1  O = 0.93 ÷ 0.25 = 3.75   Multiply all by 4 to get answer in whole number   H = 184 × 4 = 736 C = 1×4 =4  O = 3.75 × 4 = 15    So empirical formula is  C4 h736 o15   Hope it helps you  Mark as brainlist