Question

AnswerThere are 60 pebbles and 2 persons a and b. a tables 1 pebble, b takes 2 pebbles and again a takes 3 pebbles and b takes 4 pebbles and this goes on alternatively. who takes the maximum number of pebbles? Answer

Answer 1

B as A only took 1 and 3 but B took 2 and 4. If total out B is more than A

Answer 2

Question :

There are 60 pebbles and 2 persons A and B. A takes 1 pebble, b takes 2 pebbles and again a takes 3 pebbles and b takes 4 pebbles and this goes on alternatively. who takes the maximum number of pebbles?

Answer :

Both A and B have 30 pebbles each at the end.

Given :

Total no.of pebbles = 60

A takes pebbles of odd numbers .

B takes pebbles of even numbers.

To find :

Who takes the maximum number of pebbles at the end

Solution :

Total pebbles available = 60

Since A takes the first turn, the no.of pebbles he will have after 5 turns = 1+3+5+7+9 = 25

Since B takes the second turn, the no.of pebbles he will have after 5 turns = 2+4+6+8+10 = 30

As the next turn is A's , he would have to take 11 pebbles, but the no.of pebbles available is 5

Hence, the total no.of pebbles A has at the end = 25 + 5

= 30

Hence, both A and B will have 30 pebbles each at the end.

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