an organic compound contains carbon hydrogen sulphur oxygen it is found that oxygen carbon sulphur are present in mass ratio 5:3:4 while carbon sulphur and hydrogen are present in mole ratio 2:1:4 in compound if the simplest formula is Cx Hy Oz Sw then find 25-(x+y+z+w)
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Answer:
Correct option is
B
CH
3
O
The empirical formula is to be calculated as:
Element % Composition Atomic Mass Mole Ratio Simple Ratio
C 38.71 12
12
38.71
=3.22
3.22
3.22
=1
H 9.67 1
1
9.67
=9.67
3.22
9.67
=3
O 100-(38.71+9.67) =51.62 16
16
51.62
=3.22
3.22
3.22
=1
Hence the empirical formula of the compound is CH
3
O
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