Question

Question 54Two circles of radii 15 cm and 12 cm intersect each other, and the length of their common chord is 18cm. What is the distance (in cm) between their centres ?ESnimA12 +377EEEEEEB15 +1711ETimbalSharemmLEEl hombreLESLES THETELPEELLEC, 12 + 27www.EL-D18 4heਜੋAnswer: A.ਜੋ​

Answer 1

Answer:

12 + $\sqrt{63}$ cm = 12 + 7.937 = 19.937 cm

Step-by-step explanation:

Radii of chord 1 = 15 cm

Radii of chord 2 = 12 cm

Common chord = 18 cm, half of it = 9 cm

Now, by pythagorean theorem, l₁ = √$\sqrt{(15^2 - 9^2)}$(15² - 9²) = 12 cm

In the other side triangle, by pythagorean theorem, l₂ = $\sqrt{(12^2 - 9^2)}$ = $\sqrt{63}$

Now, total length = l₁ + l₂ = 12 +$\sqrt{63}$ = 19.937 cm

P.S - Sorry couldn't share the diagram.