Question

An organic compound, whose vapour density is
45, has the following percentage composition,
H = 2.22%; 0 = 71-19%; and remaining carbon.
Calculate :
(a) its empirical formula, (b) its molecular form

Answer 1

Answer:

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• Element % at. mass atomic ratio simple ratio

• C 26.59 12 = 26.59/12 = 2.21

• H 2.22 1 = 2.211 = 2.22/1

2.221=2.22

• O 71.19 16 71.19/16 = 4.44

71.1916=4.442

• (a) its empirical formula = CHO2

• (b) empirical formula mass = 45

• Vapour density = 45

• So, molecular mass = V.D × 2 = 90

• so, molecular formula = C2H2O4