Question

an organic substance containing carbon ,hydrogen and oxygen give the percentage composition as: C=40.687%,H=5.085%,O=54.228%
the vapour density of component is 59 .
calculate the molecular formula of the compound.

Answer 1

Hey friend ,

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Vapour density = 59

Molar mass = 2* vapour density

= 118

{{{TABLE IN THE PICTURE}}}

Emperical formula = C₂H₃O₂

n = $\frac{Frormula mass}{emperical formula mass}$

molecular mass = (C₂H₃O₂)₂

= C₄H₆O₄

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Hope this helped you !!