An organic substance containing Cubon hydrogen
and oxygen gave the following percentage
C = 40.681. HES:0857, = 54.22%
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Basic →100 g of compound
masses M.M moles Ratios Ratio
C 403687 12 3.3916 3.4/3.4=1 2
H 5.085 1 5.085 5.1/3.4=1.5 3
O 54.228 16 3.392 3.4/3.4=1 2
Emperical formula =C
2
H
2
O
2
Emperical mass =2×12+3×1+2×16
=24+3+32
=59
molecular mass =2×vapor density
=2×59=118
n=
E.M
M.M
=
59
118
=2
molecular formula =n×E.F=2×C
2
H
3
O
2
=C
4
H
6
O
4
Explanation:
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