An owner of a pizza small slices of pozza for rs.150 each and large slices for rs250 each one nilght he sold 5000 slices for a a total of 10.50 lakh. how many small slices were sold
Answers
Answered by
0
This question is a word problem in linear equations. The problem is solved by framing two linear equations from the information given in the question and solving them.
Let 's' be the number of small slices and 'b' the number of large slices sold on that night.
Therefore, s + b = 5000 ... eqn (1)
Each small slice was sold for Rs.150.
Therefore, 's' small slices would have fetched Rs.150s.
Each large slice was sold for Rs.250.
Therefore, 'b' large slices would have fetched Rs.250b.
Total value of sale = 150s + 250b = 10,50,000 (note the left hand side is in Rupees and hence we have to convert right hand also to Rupees from Lakhs of Rupees)
Or 150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000
Or b = 3000
We know that s + b = 5000
So, s = 5000 - b = 5000 - 3000 = 2000.
2000 small slices were sold.
Let 's' be the number of small slices and 'b' the number of large slices sold on that night.
Therefore, s + b = 5000 ... eqn (1)
Each small slice was sold for Rs.150.
Therefore, 's' small slices would have fetched Rs.150s.
Each large slice was sold for Rs.250.
Therefore, 'b' large slices would have fetched Rs.250b.
Total value of sale = 150s + 250b = 10,50,000 (note the left hand side is in Rupees and hence we have to convert right hand also to Rupees from Lakhs of Rupees)
Or 150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000
Or b = 3000
We know that s + b = 5000
So, s = 5000 - b = 5000 - 3000 = 2000.
2000 small slices were sold.
Similar questions