Question

an oxide of iodine (I=127) contains 25.4 g of iodine for 8 g of oxygen.its formula is??
Plzz explain while answering...

Answer 1

moles of l = given mass/molar mass
= 25.4/127
= 0.2 mole


mole of O= given mass/ molar mass
= 8/16
=1/2
=0.5



ratio = 2:5





thus the formula of compound is l O
2 5

Answer 2

moles of l = given mass/molar mass

= 25.4/127

= 0.2 mole

mole of O= given mass/ molar mass

= 8/16

=1/2

=0.5

ratio = 2:5

thus the formula of compound is I2O5