an oxygen containing organic compound contains 58.5 carbon, 4.06% hydrogen. 0.25 g of this compound gave 22.4 cm3 of nitrogen at STP. Calculate the empirical formula of the compound
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Explanation:
Solution :
calculation of composition:
(i). Percentage of carbon =58.53 (given)
(ii). Percentage of hydrogen =4.06 (given)
(iii) percentage of nitrogen
=
28×vol.ofN2atSTP×100
22400×Wt. Of compound
=
28×22.4×100
22400×0.246
=11.37%
(iv) percentage of oxygen =100- ("percentage of "C+" percentage of" H+" percentage of N")
=100-(58.53+4.06+11.38)=26.03
Hence, the empirical formula of the compound is C6H5NO2.
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