Math, asked by mnavneetkumar452, 8 months ago

an
Rohit lent 6,000 to Mohit at the rate of 6
% per
% per annum. Mohit returned back
6,975 to Rohit after a few years. Find out the time period.​

Answers

Answered by harshit8476
0

Step-by-step explanation:

SI=p*r*t/100

6000*6*t/100=6975

t=19.37 or 20 years

Answered by shrutica24
1

Step-by-step explanation:

P=6000, r=6%p.a. n=?

interest = P×n×r

100

975 = 6000×6×n

100

n = 975×100

6000×6

n = 975

60× 6

n = 2.7

thus, mohit returned back after 2years and 7 months

MARK ME AS BRAINLIST

Similar questions