An run contains 12 balls of which 3 are marked.if 5 balls are drawn out together.what is the probability all 3 of the marked balls are among these 5?
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Step-by-step explanation:
We have 12 balls in which 3 balls are marked and 12–3=9 balls unmarked.
5 balls can be drawn from 12 in 12C5 ways.
So the sample space is 12C5.
In the favourable case for the event we have all 3 marked balls and 2 unmarked. The 3 marked balls can be selected in 1 way and remaining 2 can be selected from unmarked in 9C2 ways.
So the required probability 9c2/12c5
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