an solution of 6.3 oxalic acid dihydrate is made upto 250 ml ,the volume of 0.1N NaOH required to completely neutralize 10ml of this solution
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We can get the answer using the formula
N1V1=N2V2
Oxalic acid is a dibasic acid as it can release two H+
Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2
=> normality = 0.2 x 2 = 0.4
For req volume of NaOH
0.4 x 10 = 0.1 x V2
=> V2 = 40 ml
N1V1=N2V2
Oxalic acid is a dibasic acid as it can release two H+
Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2
=> normality = 0.2 x 2 = 0.4
For req volume of NaOH
0.4 x 10 = 0.1 x V2
=> V2 = 40 ml
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