Question

an solution of 6.3 oxalic acid dihydrate is made upto 250 ml ,the volume of 0.1N NaOH required to completely neutralize 10ml of this solution

Answer 1

We can get the answer using the formula

N1V1=N2V2

Oxalic acid is a dibasic acid as it can release two H+

Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2

=> normality = 0.2 x 2 = 0.4

For req volume of NaOH

0.4 x 10 = 0.1 x V2

=> V2 = 40 ml