An steel wire of 20 mm diameter is bent into a circular shape of 10 m radius. If e, the modulus of elasticity is 2 x 106 kg/cm2, then the maximum
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Using bending formula,
E/R = M/I = f/y
Given d = 20 mm
So, y(max) = d/2 = 10 mm
R = 10 m = 10000 mm
E = 2 x 10^6 kg/cm^2
f(max) = 2 x 10^6 x 10 / 10000
= 2 x 10^3 kg/cm^2
Hope this helps... : )
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Given Data:
d = 20 mm
Y = d/2 = 20/2 = 10 mm
R = 10 m = 10 × 10^3 mm
E = 2 × 10^6 kg/cm^2
•Calculation:
F(max) = E/R x Y
F(max) = { 2×10^6 / 10×10^3 } x 10
•°• F(max) = 2 x 10^3 kg/cm^2
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