Question

An stone is thrown vertically upwards with the speed of 25km/h and at the same time an another is dropped at 100m high tower. Find the time & distance from ground when they cross each other.​

Answer 1

For upper stone  :            

u′=0         

x=0+21gt2

x=21×10×t2           

⟹x=5t2            ............(1)

For lower stone :            

u=25  m/s  

100−x=ut−21gt2

100−x=(25)t−21×10×t2           

⟹100−x=25t−5t2            ............(2)

Adding (1) and (2),  we get          

25t=100              

⟹t=4 s        

From (1),            

x=5×42                 

⟹x=80 m 

Hence the stone meet at a height of   20 m above the ground after 4 seconds.

Answer 2

Answer:

MARK THE UPPER ONE AS BRAINLIEST ANSWER!!!!!!!