Question

Three capacitors each of capacitance 3µF are connected in series. Equivalent capacitance will be*

(a) 4 µF

(b) 3 µF

(c) 2 µF

(d) 1 µF​

Answer 1

Answer:

correct option is b 3uf

Answer 2

Answer:

Equivalent capacitance will be 1 µF.

Explanation:

Given three capacitors each of capacitance 3 µF are connected in series.

We know that,

The Equivalent capacitance of more than two in series-

(1 / C) = (1/C1)+(1/C2)+(1/C3)+....

The Equivalent capacitance of a series combination is always less than any individual capacitor in the combination.

So,1/C = (1/3)+(1/3)+(1/3)= 3/3=1

So,C= 1 µF

We can say Three capacitors each of capacitance 3µF are connected in series. Equivalent capacitance will be 1 µF.